18.5 Gibbs Free Energy and the Equilibrium Constant

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    Gibbs Free Energy Under Nonstandard Conditions

    ΔG = ΔG° + RTlnQ (Free energy under non-standard conditions)

     

    Calculate ΔG for the following reaction at 298K when
    PN2 = 0.1atm, PH2 = 0.1atm, and PNH3 = 10.0atm.
    N2(g) + 3H2(g) → 2NH3(g)      ΔG° = -33.3kJ

    ΔG and Q
    ΔG < 0 Q < K
    ΔG > 0 Q > K
    ΔG = 0 Q = K

    Gibbs Free Energy and the Equilibrium Constant

    ΔG° = -RTlnKeq

     

    Calculate the equilibrium constant for the following reaction at 298K.
    N2(g) + 3H2(g) → 2NH3(g)      ΔG° = -33.3kJ

    ΔG° and Keq
    ΔG° < 0 Keq > 1
    ΔG° > 0 Keq < 1
    ΔG° = 0 Keq = 1